Question

suppose the orbit of a satellite is exactly 35780 km above the earth's surface. Determine the tangential velocity of the satellite.

Answer 1

The tangential  velocity of the satellite will be 3.07 km/s

Explanation :

The tangential velocity of a satellite is given by the relation;

v = √(GM/r)

G = gravitational constant = 6.67 x 10⁻¹¹

M = mass of earth = 5.972 x 10²⁴ kg

r = radius of orbit = height + radius of earth

=> r = 35780 + 6371 = 42151 km = 42151 x 10³ m

hence,

v = √(6.67 x 10⁻¹¹ x 5.972 x 10²⁴ /42151 x 10³)

= 3.07 x 10³ m/s

= 3.07 km/s

Hence the tangential  velocity of the satellite will be 3.07 km/s

Answer 2

Explanation:

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