Question

Suppose you are given a known nonzero vector Ā. The scalar product of Ā
with an unknown vector Bis zero. Likewise, the vector product of Ā with B
is zero. What can you conclude about B?​

Answer 1

Answer:

B vector has a magnitude same as A vector and direction opposite to A vector.

Explanation:

In scalar product,

$a.b \: = \: a \times b \times \cos( \alpha )$

if alpha is 180° and both vectors have same mag. then they cancel out.

Similarly, in vector product,

$a \times b \: = \: a \times b \times \sin( \alpha )$

if alpha is 0 or 180° the product will be 0.

Answer 2

Answer:

In such is case vector B must be a null vector i.e[B]=

Explanation:we know that the scaler product of two vectors A and B is given by

[A.B]=ABcos0_1)