(t-1)(t+5) how to solve
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Answered by
2
(t-1)(t+5)
t²+5t-t-5
t²+4t-5
t²+(5-1)t -5
t²+5t-t-5
t(t+5)-1(t+5)
(t-1)(t+5)
then
t=1 or t=-5
t²+5t-t-5
t²+4t-5
t²+(5-1)t -5
t²+5t-t-5
t(t+5)-1(t+5)
(t-1)(t+5)
then
t=1 or t=-5
abhi569:
Ur welcome shidhhi
Answered by
2
hey,
t( t + 5 ) -1 ( t + 5 )
t² + 5t - 1t + 5
= t² + 4t + 5
HOPE IT'S HELPS YOU...
t( t + 5 ) -1 ( t + 5 )
t² + 5t - 1t + 5
= t² + 4t + 5
HOPE IT'S HELPS YOU...
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