T^2-15 find the zeroes of this eqution and verify the relationship between the zeroes and coeffient.
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Answer:
+√15 and -√15
Step-by-step explanation:
Given a quadratic eqn such that,
t^2 - 15 = 0
Finding the Zereos, we have,
=> t^2 - (√15)^2 = 0
=> (t+√15)(t-√15) = 0
Therefore, we have,
=> t = -√15
And
=> t = +√15
Now,
Sum of roots = -b/a = 0 = √15 - √15
Product of roots = c/a = -15 = (√15)(-√15)
Hence, the roots are +√15 and -√15.
Verified.
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