(t-3)^2 - (t-3)^2
plz answar it fast
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Answered by
1
As both the values are similar, the answer would be 0.
Answered by
1
(t-3)^2 - (t-3)^2= ID= a^2 - b^2 = (a+b)(a-b)= (t-3)(t+3)
MK10:
No, it should be (t-3+t-3)(t-3-t+3)=0
Its Algebraic ID. ID = 3
SIMPLIFY USING ID 178×178-22×22
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