Question

t takes 83 mL of a 0.45 M NaOH solution to neutralize 235 mL of an HCl solution. What is the concentration of the HCl solution?

Answer 1

$\huge \bigstar ★ \huge\bold{\mathtt{\purple{A{\pink{N{\green{S{\blue{W{\red{E{\orange{R}}}}}}}}}}}}}★★$

for NaOH : 0.45

M = mol / litre

therefore , n ( NaOH ) = 0.45mole x 83 / 1000

n ( NaOH ) = 0.037 moles of NaOH .

1NaOH + 1HCI 1NaCl + 1H20

1 mole of NaOH = 1 mole of HCI

thus , n ( HCI ) = 0.037 moles

concentration of HCI = mole / litre

= 0.037 / 0.235

= 0.157

= 0.16 M