Tho blocks a and b with masses m and 2m are in contact on a horizontal frictionless surface. A force, F, is applied to block A.
What is the force exerted by block A on block B?
a) F/2
b) F/3
c) 3F/2
d) 2F/3
e) F/5
The answer is d, 2F/3, but how?
Answers
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Answer:
2F/3
Explanation:
I believe that a = m, and b = 2m respectively?
Consider the acceleration of the objects in contact:
a = F/m + 2m = F / 3m,
If we apply the force on the object of mass m:
F/3m * m = F/3
And the force applied on the object of mass 2m would be:
F/3m * 2m = 2F/3
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