Question

Take 5ml of hydrogen peroxide (H2O2) solution in a test tube. Add some manganese dioxide (MnO2 ) into it (3)
a. Which is the gas evolved ?
b. What is the function of MnO2 in this reaction?
c. Which are the substances remaining in the test tube when the reaction is over?​

Answer 1

Answer:

a. The reaction liberates oxygen gas

b.MnO2 acts as a catalyst and increases the speed of the reaction without itself undergoing any chemical change

c. The substance remaining are Water and Oxygen gas

Explanation:

Answer 2

Answers to reaction with Hydrogen peroxide are as follows -

a. The gas evolved in the reaction is oxygen.

b. The manganese dioxide acts as a catalyst in the reaction. It lowers the activation energy for ease of occurrence of reaction.

c. The substance remaining in the test tube is water.

• The balanced chemical equation of hydrogen peroxide decomposition in presence of manganese dioxide is as follows -
• H2O2 --MnO2--> 2H2O + O2. In the reaction, H2O2 represents hydrogen peroxide, MnO2 represents manganese dioxide, H2O represents water and O2 represents oxygen.