Math, asked by rahulagrawal2, 1 year ago

tan ^2x+sec^2x=3 solve this problem

Answers

Answered by siddhartharao77
1
Given, tan^2 x + sec^2 x = 3 can be written as

            tan^2 x + 1+ tan^2 x = 3

           2 tan^2 x = 3 - 1

           2 tan^2 x = 2

             tan^2 x = 2/2

                          = 1

                tan x = -1,1

                      x = pi/4, 3pi/4,5pi/4,7pi/4.


Hope this helps!
Answered by Rakshitsaini
0
Tan^2x+1=sec^2x
So tan^2x =1
X=45°
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