tan (45 + theta) × tan (135 + theta) =1
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Answered by
14
LHS = tan(45 + theta)× tan(90 + (45 + theta))
=tan(45+ theta) xcot (45 + theta)
=tan(45 + theta×1/tan(45+ theta)
=1 = RHS
=tan(45+ theta) xcot (45 + theta)
=tan(45 + theta×1/tan(45+ theta)
=1 = RHS
kumud92:
thax
Answered by
24
Now,
tan (45° + θ) × tan (135° + θ)
= tan (45° + θ) × tan {90° + (45° + θ)}
= tan (45° + θ) × cot (90° + θ)
= 1, since tanA cotA = 1
Hence, proved.
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