Question

tan (A+B-C)=root3 and sec(B+C-A)=1 find A,B,andC

Answer 1

Answer:

Step-by-step explanation:

tan[a+b-c]=root3

tan[a+b-c]=tan60

a+b-c=60_____1)

now,sec[b+c-a]=1

sec[b+c-a=sec[0}

b+c-a=0______2)

now u can solve the equations ok............