tan(A+B)=tanA+tanB/1-tanAtanB
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Answered by
1
Step-by-step explanation:
L:H:S = tan(a+b)
= sin(a+b)/cos(a+b)
= (sin a.cos b+cos a.sin b)/(cos a.cos b-sin a.sin b)
devide the numerator and denominator by cos a.cos b
= (sin a/cos a + sin b/cos b) / (1-sin a.sin b/cos a.cos b)
= (tan a + tan b)/(1 - tan a.tan b)
= R:H:S
Answered by
0
Answer:
take a=b
tan2a=2tana/1-tana2
tan2a×sec2a÷2=tans
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