Math, asked by Sahanagouda, 1 year ago

tan A-sin A/ sin^2A = tanA / 1+ cosA...plz answer fir this ..i ll make u as brainliest

Answers

Answered by syedsaqeeb66

0

Answer:

Step-by-step explanation:

tanA- sinA/sin2a

tanA-sinA/sin2A

tanA -sina/1+cos2A

tanA-sina/(sin2a +cos2A)+cos2a

tanA-sina/sin2A+cos2A+cos2a

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