Math, asked by spninawe, 11 months ago

tan pi by 4 + theta = 1-tantheta/1+tantheta

Answers

Answered by Anonymous

1

Step-by-step explanation:

tan(A+B) = tanA + tanB/1-tanA*tanB

tan(π/4 + O)

= tan(π/4)+tanO / 1-tan(π/4)*tanO

= 1 + tanO / 1 - tanO

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