Math, asked by manikmadan7871, 1 year ago

tan+sec=l sec=l2+1\2l

Answers

Answered by mantasakasmani
0
I = tan0 + sec0
I - sec0 = tan0
l² + sec²0 - 2 l sec0 = tan²0
= sec²0 - 1

So sec0 = (l² + 1) / 2l

this is your answer......
Similar questions