tan+sec=l sec=l2+1\2l
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I = tan0 + sec0
I - sec0 = tan0
l² + sec²0 - 2 l sec0 = tan²0
= sec²0 - 1
So sec0 = (l² + 1) / 2l
this is your answer......
I - sec0 = tan0
l² + sec²0 - 2 l sec0 = tan²0
= sec²0 - 1
So sec0 = (l² + 1) / 2l
this is your answer......
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