Question

tan square A minus sin square is equal to tan square A×sin squareA.proove

Answer 1

Here is the solution :

L.H.S = Tan² A - Sin² A,

Simplifying L.H.S,

=> (Tan A + Sin A)(Tan A - Sin A)
[Since, a² - b² = (a+b)(a-b)

=> ((Sin A/CosA) + Sin A)*((SinA /CosA )- Sin A )
=> (((Sin A + Sin A Cos A)Cos A ) (((Sin A - Sin ACos A)/Cos A)))

=> ((Sin² A - Sin²A Cos² A)/Cos ² A)
=> ((Sin² A ( 1 - cos² A)/Cos² A))
=>( Sin² A * Sin ² A )/ Cos ² A,

=> Sin² A * Tan² A,

=> Tan² A - Sin²A = Tan²A*Sin²A,

Therefore : Hence proved !

Hope you understand, Have a great day !
Thanking you, Bunti 360 !

Answer 2

Hello its Devansh

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