tan theta=5/4 ,find the value of sec theta
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Step-by-step explanation:
let thitha = A TanA=5/4
Perpendicular/base = 5/4 P = 5 and B = 4 Using pythagoras theorem we get H = root of square of 5 and square of 4 (square of p + square of b = square of h) H =ROOT OF 25 + 16 = ROOT OF 41 AND HENCE H IS ROOT 41 sec A = H/B = root 41 / 4
strongshantu:
thanks bro
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