Question

tan theta =p/q find psintheta-q cos theta / psin thete+q cos theta

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Answer 1

so ur answer is

given in the attachment

hope it helps u

Answer 2

Answer:

(1) $\frac{p^{2} - q^{2} }{p^{2} + q^{2}}$

Explanation:

given, tanθ = p/q

Required to find: $\frac{psinθ - qcosθ}{psinθ + qcosθ}$

Dividing the numerator and denominator by "cosθ":

$\frac{\frac{psinθ - qcosθ}{cosθ}}{\frac{psinθ + qcosθ}{cosθ} }$ = $\frac{ptan - q}{ptan + q}$ = $\frac{p \frac{p}{q} - q }{p \frac{p}{q} + q }$ = $\frac{\frac{p^{2} - q^{2} }{p} }{\frac{p^{2} + q^{2} }{p}}$ = $\frac{p^{2} - q^{2} }{p^{2} + q^{2} }$

Due to some reason, the equations are appearing blurry.

I'm so sorry for that.

Hope it helps somehow. :)