Question

tan² 66º - cot² 24º = 0 without using trigonometric table prove that​

Answer 1

Answer:

A.T.Q

L.H.S = tan²66° — cot²24° | R.H.S = 0

= tan²66° — cot²24°

= tan²(90—24)° — cot²24°

---------------(as, 66= 90-24)

= cot²24 — cot²24

------------{as, tan(90-¢) = cot¢}

= 0

hence, L.H.S = R.H.S (i.e. 0)

therefore, tan²66° — cot²24° = 0

hence proved..

Step-by-step explanation:

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Answer 2

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