Math, asked by riyay022918, 9 months ago

tan3x=cot 5x,(0<x<2Π)​

Answers

Answered by rajeshbhu555
0

Step-by-step explanation:

tan10x2tan5x1−tan25x1−tan25x3tan25xtan5x5xxx=cot5x=1tan5x=2tan25x=1=±13–√=π6+nπ,−π6+nπ,5π6+nπ,11π6+nπ=15nπ+π30,15nπ−π30,π6+15nπ,15(π+5π6+nπ) repeated solution=15nπ+π30,15nπ−π30,π6+15nπ

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