Math, asked by raj198, 1 year ago

(tanA/1-cotA)+(cotA/1-tanA)=1+secAcosecA

Answers

Answered by abhi178
3
tanA/(1-cotA) +cotA/(1-tanA)

=>tan^2A/(tanA-1)+cotA/(1-tanA)

=>(tan^2A-cotA)/(tanA-1)

=>(tan^3A-1)/tanA.(tanA-1)

=>(tan^2A+tana+1)/tanA

=>tanA+cotA+1

=>sinA/cosA+cosA/sinA +1

=>(sin^2A+cos^2A)/sinA.cosA+1

=>1/sinA.cosA+1

=>secA.cosecA +1=RHS

abhi178: i hope you understand
abhi178: please mark as brainliest
raj198: i did not understand
raj198: plz give the solution in step by step
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