Question

tanA-cotA/sinAcosA=tan^A-cot^A

Answer 1

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Answer 2

Solution :

LHS =(tanA-cotA)/(sinAcosA)

= tanA/sinAcosA

- cotA/sinAcosA

= (sinA/cosA)/sinAcosA

- (cosA/sinA)/sinAcosA

= 1/cos²A - 1/sin²A

= sec²A - cosec²A

= ( 1+tan²A )-( 1 + cot²A )

= 1 + tan²A - 1 - cot²A

= tan²A - cot²A

= RHS