Math, asked by duhafayyaz770, 10 months ago

tanA+secA-1/tanA-secA+1=tanA+secA

Answers

Answered by sultan85
9

tanA+secA-1/tanA-secA+1=tanA+secA

L.H.S=tanA+secA-(sec^2A-tan^2A)/tanA-secA+1

tanA+secA-(secA+tanA)(secA-tanA)/tanA-secA+1

tanA+secA (1-(secA-tanA)/tanA-secA+1

tanA+secA (1-secA+tanA)/1-secA+tanA

tanA+secA R.H.S

HENCE PROOF

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