tanA+secA=p then tanA-secA=
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secA + tanA = p
1/cosA + sinA/cosA = p
(1 + sinA)/cosA = p
(1 + sinA)^2/cosA^2 = p^2 [squaring both sides]
(1 + sinA)^2/(1 - sinA^2) = p^2 [ since cosA^2 + sinA^2 = 1]
(1 + sinA)^2/(1 + sinA)(1 - sinA) = p^2
(1 + sinA)/(1 - sinA) = p^2 [the common part getting cancelled]
2/2sinA = (p^2 + 1)/(p^2 - 1) [By componendo and dividendo we get]
1/sinA = (p^2 + 1)/(p^2 - 1)
Therefore
sinA = (p^2 - 1)/(p^2 + 1) [Answer]
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1/cosA + sinA/cosA = p
(1 + sinA)/cosA = p
(1 + sinA)^2/cosA^2 = p^2 [squaring both sides]
(1 + sinA)^2/(1 - sinA^2) = p^2 [ since cosA^2 + sinA^2 = 1]
(1 + sinA)^2/(1 + sinA)(1 - sinA) = p^2
(1 + sinA)/(1 - sinA) = p^2 [the common part getting cancelled]
2/2sinA = (p^2 + 1)/(p^2 - 1) [By componendo and dividendo we get]
1/sinA = (p^2 + 1)/(p^2 - 1)
Therefore
sinA = (p^2 - 1)/(p^2 + 1) [Answer]
Please mark as brain list please
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tanA -secA=q this answered
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