Math, asked by Rathneshwaran, 1 year ago

Taps A and B can fill an empty tank in 3 hours and 5 hours respectively tap C can empty the full tank in 7 1/2 hours off all three taps are open at the same time in how many hours will the tank be full

Answers

Answered by dineshkannan135
56

Answer:

5/2 hours

Step-by-step explanation:

A's 1 hr work = 1/3

B's 1 hr work = 1/5

C's 1 hr Work = -2/15

(A+B+C)'s 1 hr work = (1/3) + (1/5) + (-2/15)

                                = 2/5

So If all the pipes are opened at the same time they will take 5/2 hours to fill the tank.

Answered by ponnuchinnu86
3

Answer:

So If all the pipes are opened at the same time they will take 5/2 hours to fill the tank.

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