Question

Teacher asked a student to say a two digit number what is the probability of that number being 17

Answer 1

Hey friend here is your answer

Probability = Favourable outcomes / Total outcomes
Total outcomes = 2 digit no = 90
Favourable outcomes = 1

Probability = 1 / 90.

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Answer 2

Answer:

Required probability is $\frac{1}{90}$

Step-by-step explanation:

Given, a teacher asked a student to say a two digit number.

We want to find the probability that what is the probability of that number being 17.

We know that,

Total numbers of two digits numbers $= 90$

and we know 17 come only one time in all two digit numbers.

So,it is clear that the student can say 17 only one time

Therefore the probability is $\frac{1}{90}$

which cannot be simplified.

Hence the probability that a 2-digit number being 17 is $\frac{1}{90}$

This is a problem of Algebra.

Some important Algebra formulas.

(a + b)² = a² + 2ab + b²

(a − b)² = a² − 2ab − b²

(a + b)³ = a³ + 3a²b + 3ab² + b³

(a - b)³ = a³ - 3a²b + 3ab² - b³

a³ + b³ = (a + b)³ − 3ab(a + b)

a³ - b³ = (a -b)³ + 3ab(a - b)

a² − b² = (a + b)(a − b)

a² + b² = (a + b)² − 2ab

a² + b² = (a − b)² + 2ab

a³ − b³ = (a − b)(a² + ab + b²)

a³ + b³ = (a + b)(a² − ab + b²)

Know more about Algebra,

1) https://brainly.in/question/13024124

2) https://brainly.in/question/1169549

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