Question

(x²+x+1)²+(x²-x+1)²
plz solve fast

Answer 1

(x^2+x+1)^2+(x^2-x+1)^2=
(x^2)^2+(x)^2+(1)^2+2(x^2)(x)+2(x^2)(1)+2(x)(1)+(x^2)^2+(-x)^2+(1)^2+2(x^2)(-x)+2(x^2)(1)+2(-x)(1)
=x^4+x^4+2x^3-2x^3+x^2+x^2+2x-2x+1+1
=2x^4+2x^2+2

Answer 2

Using the identity,

(a+b+c)2=a2+b2+c2+2ab+2bc+2ac

The expression can be expanded as

(x2−x+1)2=(x2)2+(x)2+(1)2+2(x2)(−x)+2(−x)(1)+2(1)(x2)

Simplifying the above obtained expression, we get

x4+x2+1−2x3−2x+2x2

Which is the required answer.

THANKS!!! please mark as a brainliest answer!!