Question

tell me the answer that I circle one

Answer 1

Here is the answer of this question

Answer 2

In triangle PQS and PRS we get,
PQ=PR(GIVEN)
QS=QR(GIVEN)
PS=PS(COMMON)
Therefore, ∆PQS=~∆PRS
Then, angle QPS=angle RPS(corresponding parts of congruent triangles)
angle QSP=angle RSP(corresponding parts of congruent triangles)
Then QSP+RSP=180°
=>QSP+QSP=180°(since angle QSP=angle RSP)
=>2 QSP=180°
=>QSP=90°
=>QSP=RSP=90°
Hence PS is perpendicular to QR