Question

Ten tuning forks are arranged in increasing order of frequency in such a way that any two nearest tuning forks produce 4 Beats per second. The highest frequency is twice that of the lowest. Calculate possible highest and lowest frequencies of the forks.

Answer 1

Let the frequency of first tuning fork is x then then we add on 4 to x to get frequency of next fork so by doing this the frequency of the last fork will be 36+x .
Now since it is given that the frequency of last tuning fork is double than that of first we get other frequency of last tuning fork = 2x
Now by solving these two equations we get
x = 36
therefore least frequency is 36 and max. is 72.

Answer 2

Answer: hi there this is the answer to the above one

Let the frequency of first tuning fork is x then then we add on 4 to x to get frequency of next fork so by doing this the frequency of the last fork will be 36+x .

Now since it is given that the frequency of last tuning fork is double than that of first we get other frequency of last tuning fork = 2x

Now by solving these two equations we get

x = 36

therefore least frequency is 36 and max. is 72.

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