Question

Ten years ago, a father was 10 times as old as his son. Form a linear equation expressing their present age​

Answer 1

Answer:

Let us consider that the present age of the father and the son are x and y years.

So, 10 years ago, the father was (x - 10) years old.

Given that :

x - 10 = 10y

=> x - 10y = 10,

which is the required linear equation.

Answer 2

Step-by-step explanation:

Let the fathers age be x and his sons age be h

so ATQ

x-10 = 10(y-10)

x-10 = 10y -100

x-10y+90=0