Question

ten years ago a father was 6times as old az his son after 10 years he twice as his son find their present age​

Answer 1

Answer:

The given question is solved in the uploaded photos

Step-by-step explanation:

Answer 2

Answer:

present age of

father is 60

son is 25

Step-by-step explanation:

let father's present age be x

and son's present age be y

10 yrs ago

father's age was  x-10

and son's age was  y-10

ATQ

6(y-10)=x-10

6y-60=x-10

6y-x = 50 (i)

after 10 yrs

age of father will be x+10

and of son will be y+10

ATQ

2(y+10)=x+10

2y +20 =x+10

2y - y = -10 (ii)

Now solving eq (i) and(ii)

we get,

x = 60

y = 25