Ten years ago, the age of a person’s mother was three times the age of her son. Ten years hence, the mother’s age will be two times the age of her son. Their present ages are
Answers
Answer:
Say,
the age of son was x and mother's age was 3x.
After ten years: Mother's age will be (3x + 10) +10
and son's age will be (x + 10) + 10.
Given that, mother's age is twice that of son after ten years.
(3x + 10): (x + 10) = 70: 30 = 7: 3.
- Question based on linear equation with two variables so, we will solve this question by setting up equation. In the Q given that we have to find present age of mother and his son as per the given clue in question.
- Ten years ago, the age of a person’s mother was three times the age of her son.
- Ten years hence, the mother’s age will be two times the age of her son.
- By Substracting eq (l) and (ll) we get :-
- By solving we get here :-
- Putting the value of y in eq (I):-
MORE TO KNOW -
Definition of Equation:-
→ A statement of equality which contains one or more unknown quantity or variable (literals) is called an equation.
Definition of Linear Equation :-
→ An equation involving only linear polynomials is called a linear equation
Definition of Solution of Linear Equation :-
→ A value of the variable which when substituted for the variable in an equation, makes LHS = RHS is said to satisfy the equation and is called a salution or root of the equation.
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