Question

Ten years hence, a man's age will be twice the age of his son. Ten years ago, man was four times as old as his son. Find their present ages

Answer 1

let the man's age be 'x' and son's age be 'y' =x+10=2(y+10) eq1 and x-10=4(y-10) by solving the two equations we get present age of man is'50'years and son is '20'years