tennis ball projected at an angle attain a range R=78m if the velocity imported to the ball by rocket is 3oms-1 calculate angle take g = 10ms-1
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7
When a ball is hit by a tennis, it performs projectile motion
Let u be the velocity with which ball is projected at an angle theta
As given in the Question,
Velocity of the ball,
u = 30 m/s
Range is also given
R = 78 m
We know the formula of Range in projectile Motion as,
R = (u^2/g) (Sin2theta)
Putting the values we get,
78 = (30^2/9.8) (SIn2theta)
78 = (900/9.8) (Sin2theta)
Sin2 theta = (78 * 9.8) / 900
Sin2theta = 13*49 / 750
2 SIntheta Cos theta = 637 / 750
Let u be the velocity with which ball is projected at an angle theta
As given in the Question,
Velocity of the ball,
u = 30 m/s
Range is also given
R = 78 m
We know the formula of Range in projectile Motion as,
R = (u^2/g) (Sin2theta)
Putting the values we get,
78 = (30^2/9.8) (SIn2theta)
78 = (900/9.8) (Sin2theta)
Sin2 theta = (78 * 9.8) / 900
Sin2theta = 13*49 / 750
2 SIntheta Cos theta = 637 / 750
Answered by
5
Answer:
30°
Explanation:
R=u^2sin2thetha/g
78=30^2sin2theta/10
78*10=30^2sin2theta
780=900sin2theta
780\900=sin2theta
0.8667=sin2theta
Inverse of 0.8667=60
60°=sin2theta
60°\2=sin2theta\2
Sin theta =30°
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