Question

test the divisibility of 1041966 numbers by 3,9​

Answer 1

Answer:

yes , 1041966 is divisible by 3 and 9

Step-by-step explanation:

to check the devisibility of a number by 3 and 9

we simply have to add all the number of give number.. then, we have to check the sum of divisible by 3 and 9.... this rule if for 3 and 9 both

since , we add 1041966

1+0+4+1+9+6+6 = 27

and 27 is devisible by both 3 and 9

Hope it helps ... please mark me as brainest...

Answer 2

Answer:

it is divisible by 3 and 9

Step-by-step explanation:

Basically, we will see if the sum of the digits is divisible by 9 and 3. If it is, then the actual number is also divisible by 9 and 3

So,

1041966

1+0+4+1+9+6+6 = 27

27/9=3 and 27/3=9

therefore, 1041966 is divisible by 3 and 9

HOPE IT HELPS YOU