Math, asked by apm43, 10 months ago


10x + 3y = 75 \\ 6x - 5y = 11
solve these equations.... ​

Answers

Answered by rani49035
5

Answer:

10x + 3y = 75 ..... (i)

6x -5y = 11 .........(ii)

multiply (i) by 5 and (ii) by 3 then add both the equations..

50x + 15y = 375..

18x - 15y = 33..

68x = 408

x = 6

put x = 6 in any of the equations..

then y = 5

hope this will help you..

pls follow me

Answered by Anonymous
3

Given ,

 \to 10x + 3y = 75 ----- (i)

 \to 6x - 5y = 11 ----- (ii)

 \starMultiply the eq (i) by 6 and eq (ii) by 10 , we get

 \to 60x + 18y = 450 ----- (iii)

 \to 60x - 50y = 110 ----- (iv)

 \starSubtract eq (iv) from eq (iii) , we obtain

 \sf \implies</p><p>60x + 18y - (60x - 50y) = 450 - 110 \\  \\  \sf \implies</p><p>60x + 18y - 60x + 50y = 340 \\  \\  \sf \implies</p><p>68y = 340 \\  \\  \sf \implies</p><p>y = 5

 \starPut the value of y = 5 in eq (i) , we obtain

 \sf \implies 10x + 3(5) = 75 \\  \\  \sf \implies</p><p>10x + 15 = 75 \\  \\  \sf \implies</p><p>10x = 60 \\  \\  \sf \implies</p><p>x = 6</p><p>

Hence , the required values of x and y are 6 and 5

Similar questions