Question

$25x^{2}-2x+5=0$

Answer 1

$25 {x}^{2} - 2x + 5 = 0 \\ x = \frac{ - b \frac{ + }{} \sqrt{ {b}^{2} - 4ac} }{2a} \\ x = \frac{2 \frac{ + }{} \sqrt{4 - 125} }{50} \\ x = \frac{ 2 \frac{ + }{} \sqrt{ - 121} }{50} = \frac{2 \frac{ + }{}11i }{50}$

Therefore x has no real roots and

x = 1/25 + 11i/50 and 1/25 - 11i/50

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