Question

$2y {}^{2} - 7y + 2 = 0$
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Answer 1

2y² + 7y + 5 = 0

Here a = 2 , b = 7 , c = 5

α,β are 2 zeroes

So sum of the zeroes = α + β = - b/ca= -7/2

Product of zeroes = αβ =  c/a = 5/2

Now just put the values

α + β + αβ = ( α + β) + αβ

= -7/2 + 5/2

= -2/2 = -1

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