Question

Find three consecutive odd number whose sum is 147

Answer 1

Answer:

47,49,51

Step-by-step explanation:

Let the numbers be x, x+2 and x+4

x+x+2+x+4=147

3x+6=147

3x=147-6

3x=141

x=141/3

x=47

Thus

x=47

x+2=49

x+4=51

Answer 2

Answer:

let the no be x,x+4,x+2

Now

x+x+4+x+2=147

3x+6=147

3x=141

x=47

Hence the 3 no are

47,49,51

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