please solve it fast today is my exams......
Answers
Answer:
Hey there!
5 {}^{x - 3} \times 3 {}^{2x - 8} = 2255
x−3
×3
2x−8
=225
using \: a {}^{m + n} = a {}^{m} \times a {}^{n}usinga
m+n
=a
m
×a
n
5 {}^{x} \times 5 {}^{ - 3} \times 3 {}^{2x} \times 3 {}^{ - 8} = 2255
x
×5
−3
×3
2x
×3
−8
=225
5 {}^{x} \times \frac{1}{5 {}^{3} } \times 3 {}^{2x} \times \frac{1}{3 {}^{8} } = 2255
x
×
5
3
1
×3
2x
×
3
8
1
=225
5 {}^{x} \times \frac{1}{125} \times 3 {}^{2x} \times \frac{1}{6561}5
x
×
125
1
×3
2x
×
6561
1
5 {}^{x} \times \frac{1}{820125} \times 3 {}^{2x} = 2255
x
×
820125
1
×3
2x
=225
5 {}^{x} \times \frac{1}{820125} \times 9 {}^{x} = 2255
x
×
820125
1
×9
x
=225
(5 \times 9) {}^{x} = \frac{1}{820125} = 225(5×9)
x
=
820125
1
=225
45 {}^{x} \times \frac{1}{820125} = 22545
x
×
820125
1
=225
multiply both sides by 820125
820125 \times \frac{1}{820125} \times 45 {}^{x} = 820125 \times 225820125×
820125
1
×45
x
=820125×225
45 {}^{x} = 18452812545
x
=184528125
log_{45}(45 {}^{x} ) = log_{45}(184528125)log
45
(45
x
)=log
45
(184528125)
using \: log_{a}(a {}^{x} ) = xusinglog
a
(a
x
)=x
x = log_{45}(184528125)x=log
45
(184528125)
Alternative form (5)
P.S. : Point out mistakes if any! :p
Hope it helps!
follow me?!!!!!............
.......