Question

$(ax ^{3} + 2) ^{2} = a^{2} x ^{6} + x ^{3} + 4. then \: find \: a$
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Answer 1

Answer:

1/4

Step-by-step explanation:

Solve LHS

a^{2} x ^{6} +4a x ^{3} + 4 =a^{2} x ^{6} + x ^{3} + 4.

4ax ^{3} =x ^{3}

4a=1

a=1/4

Hope it helps you. Mark it as a brainliest answer please

Answer 2

Step-by-step explanation:

Given : ( ax^3+2)^2=a^2x^6+x^3+4

a^2x^6+4+4ax^3=a^2x^6+x^3+4

4ax^3=x^3

4ax^3-x^3=0

x^3(4a-1)=0

So either x=0 or 4a-1=0

or 4a=1

a=1/4

Hope it helps!.

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