Question

$\footnotesize\sf\red{Calculate \: the \: effective \: resistance \: between \: points} \\ \footnotesize\sf\red{ A \: \: and \: \: F \: \: from \: the \: diagram \: \: given \: \: \: above. \: \: \: \: \: \: \: \: \: }$
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Answer 1

Explanation:

The 3 three ohm resistor at top are in parallel so net resistance will be ,

=> 1/R = 1/R_1 + 1/R_2 + 1/R_3

=> 1/R = 1/ 3 * 3

=> 1/R = 1/1 Ω

=> R = 1 Ω

Again Similarly at bottom the three 3 ohm resistance are in parallel .

=> R = 1 Ω

Again these two 1Ω net resistance are in parallel. So net resistance will be ,

=> 1/R = 1/1 + 1/1

=> 1/R = 2/1Ω

=> R = ½ Ω

Now this half ohm , two two ohm resistances are in series , so net resistance

=> R =( ½ + 2 + 2 ) Ω

=> R = (4 + 0.5 ) Ω

=> R = 4.5 Ω

Answer 2

We know that when resistance are connected in series then net resistance is sum of individual resistances.

And in case of parallel say R¹ and R² are in parallel , then ,

$\sf \dfrac{1}{R_n}=\dfrac{1}{R_1}+\dfrac{1}{R_2}$

Now refer to attachment .