Question

$\frac{2}{5} (3x - 2) = \frac{3}{4} (x + 1)$
solve please​

Answer 1

Answer:

2/5 ( 3x - 2 ) = 3/4 ( x + 1 )

6x/5 - 4/5 = 3x/4 + 3/4

6x/5 - 3x/4 = 3/4 + 4/5

6x×4 - 3x×5 /20 = 3×5 + 4×4 / 20

24x - 15x / 20 = 15 + 16 / 20

9x/20 = 31/20

9x = 31/20 × 20

9x = 31

x = 31/9

x = 3.444

i hope it helps you

Answer 2

$\large\underline\purple{\bold{Solution :- }}$

$\rm : \implies \:\dfrac{2}{5} (3x - 2) \: = \: \dfrac{3}{4} (x + 1)$

$\rm : \implies \:\dfrac{6x - 4}{5} = \dfrac{3x + 3}{4}$

$\rm : \implies \:4(6x - 4) = 5(3x + 3)$

$\rm : \implies \:24x - 16 = 15x + 15$

$\rm : \implies \:24x - 15x = 15 + 16$

$\rm : \implies \:9x \: = \: 31$

$\rm : \implies \:x \: = \: \dfrac{31}{9}$

Verification

Consider LHS,

$\rm : \implies \:\dfrac{2}{5} (3x - 2)$

On substituting the value of x, we get

$\rm : \implies \:\dfrac{2}{5} (3 \times \dfrac{31}{9} - 2)$

$\rm : \implies \:\dfrac{2}{5} (\dfrac{31}{3} - 2)$

$\rm : \implies \:\dfrac{2}{5} \times \dfrac{25}{3}$

$\rm : \implies \:\dfrac{10}{3}$

Now,

Consider RHS,

$\rm : \implies \:\dfrac{3}{4} (x + 1)$

On substituting the value of x, we get

$\rm : \implies \:\dfrac{3}{4} (\dfrac{31}{9} + 1)$

$\rm : \implies \:\dfrac{3}{4} \times \dfrac{40}{9}$

$\rm : \implies \:\dfrac{10}{3}$

$\rm : \implies \:LHS \: = \: RHS$

$\large{\boxed{\boxed{\bf{Hence, \: x \: = \: \dfrac{31}{9} }}}}$