Question

$\frac{2 + \sqrt{3} }{2 - \sqrt{3} }$
rationalise the denominator

Answer 1

Hope it helps you.....✌✌

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Answer 2

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✴✴$\underline{Here \: is \: your \: answer↓}$⬇⏬⤵

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$\boxed{ RATIONALISE:-)}$

$\bf{ = \frac{2 + \sqrt{3} }{2 - \sqrt{3} } .}$

$\bf{ = \frac{2 + \sqrt{3} }{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} } .}$

$\bf{ = \frac{ {(2 + \sqrt{3} )}^{2} }{ {2}^{2} - { (\sqrt{3}) }^{2} } .}$

$\bf{ = \frac{ {2}^{2} + {( \sqrt{3}) }^{2} + 2 \times 2 \times \sqrt{3} }{4 - 3} .}$

$\bf{ = 4 + 3 + 4 \sqrt{3} .}$

$\boxed{ = 7 +4 \sqrt{3} .}$

✅✅ Hence, it is rationalised.✔✔.

✴✴$\boxed{THANKS}$✴✴

☺☺☺$\bf \underline{Hope \: it \: is \: helpful \: for \: you}$✌✌✌.