Question

$( \frac{ - 3}{5} ) {}^{6} \times ( \frac{ - 3}{5} ) {}^{4 } = ( \frac{ - 3}{5}) { {}^{2x} }$
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Answer 1

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$</p><p>(\frac{ - 3}{5} ) {}^{6} \times ( \frac{ - 3}{5} ) {}^{4 } = ( \frac{ - 3}{5}) { ^{2x} }</p><p>$

As the bases are same, values of the powers will be same.

In easy words, as

$</p><p>( \frac{ - 3}{5} ) {}^{6} \times ( \frac{ - 3}{5} ) {}^{4 } = ( \frac{ - 3}{5}) { {}^{2x} } \\ \implies6 \times 4 = 2x \\ \implies24 = 2x \: \: \: \: \: \: \\ \implies \frac{24}{2} = x \: \: \: \: \: \: \: \: \\ \implies12 = x \: \: \: \: \: \: \: \: \: </p><p>$

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x = 12

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