The product of the digits of two digit number is 18 and difference of digits is 3. If the digit in the tens place is bigger than that of unit place , find the number.
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Let, the tens place digit be x and unit digit be y.
Since ,The product of the digits of two digit number is 18 .
So, xy = 18
=> x = 18/y .....(1)
Also, difference of digits is 3 is x is bigger than y .
So, x - y = 3 .....(2)
From (1) -
18/y - y = 3
=> y^2 + 3y - 18 = 0
=> y^2 + 6y - 3y - 18 = 0
=> y(y+6) - 3(y+6) = 0
=> (y+6) (y-3) = 0
=> y = -6 or 3
=> y = 3 [ since negative number is not possible ]
put this value in equation (2), we get
x - 3 = 3
=> x = 6
therefore, tens place digit is 6 and unit place digit is 3
Hence, the number is 6×10+3 = 63
【 Hope it help you 】
Let, the tens place digit be x and unit digit be y.
Since ,The product of the digits of two digit number is 18 .
So, xy = 18
=> x = 18/y .....(1)
Also, difference of digits is 3 is x is bigger than y .
So, x - y = 3 .....(2)
From (1) -
18/y - y = 3
=> y^2 + 3y - 18 = 0
=> y^2 + 6y - 3y - 18 = 0
=> y(y+6) - 3(y+6) = 0
=> (y+6) (y-3) = 0
=> y = -6 or 3
=> y = 3 [ since negative number is not possible ]
put this value in equation (2), we get
x - 3 = 3
=> x = 6
therefore, tens place digit is 6 and unit place digit is 3
Hence, the number is 6×10+3 = 63
【 Hope it help you 】
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