Question

${\huge {\bf {\red {\underline {\underline { Physics \: Question}}}}}$
A Boeing 747 aircraft has a landing speed of 72 m/s, and upon landing it is able to come to a stop in 2,000 m. Assuming constant deceleration, how long would it take for a Boeing 747 to come to a full stop?

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Answer 1

Explanation:

t * 36 m/s = 2,000 m. So t = 2,000/36. t = 55.5555555… We’ll round that to 56 seconds.

Answer 2

$\underline{\underline{\sf{\maltese\:\:Question}}}$

• A Boeing 747 aircraft has a landing speed of 72 m/s, and upon landing it is able to come to a stop in 2,000 m. Assuming constant deceleration, how long would it take for a Boeing 747 to come to a full stop?

$\underline{\underline{\sf{\maltese\:\:Answer}}}$

• It would take 56 seconds for a Boeing 747 to come to a full stop

$\underline{\underline{\sf{\maltese\:\:Calculations}}}$

Considerations :

• The Final velocity is zero
• The initial speed is the speed of landing

Equation to calculate acceleration  :

$\Large\boxed{\sf{V_{f}^{2}=V_{i}^{2}+2 \cdot a \cdot x}}$

Time it takes to stop  :

$\large\boxed{\sf{v_{f}=V_{i}+a \cdot t}}$

$\sf{\implies t=\dfrac{v_{f}-v_{i}}{a}}$

$\sf{\implies \displaystyle t=\frac{0 \frac{m}{s}-72 \frac{m}{s}}{-1,296 \frac{m}{s^2}}}$

⇒ t ≈ 56 s