Question

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The pair of linear equations 2 x + 7 y = k, Kx + 21 y = 18 has infinitely many solutions then find k?

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Answer 1

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2x+7y=k

2x+7y=kkx+21y=18

Infinitely many soln. condition

a1/a2=b1/b2=c1/c2

2/k=7/21=k/18

Now, 2*21=k*7

42=7k

k=6←

Now, 7*18=21*k

7*18/21=k

6=k←

From these two +6 is common.

• so k=6

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Answer 2

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2x+7y=k

2x+7y=kkx+21y=18

Infinitely many soln. condition

a1/a2=b1/b2=c1/c2

2/k=7/21=k/18

Now, 2*21=k*7

42=7k

k=6←

Now, 7*18=21*k

7*18/21=k

6=k←

From these two +6 is common.

so k=6

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