Question

${ \huge\fbox \pink {Q}\fbox \blue {u} \fbox \purple {e} \fbox \green{s} \fbox \red {t} \fbox \orange {i} \fbox{o} \fbox \gray{n}}$

[Question 1]↓
${ \bold \gray{12x {}^{2} - 7x + 1}}$
[Question 2] ↓
${ \bold \gray{2x {}^{2} + 7x + 3}}$


Note:-
❎Irrelevant answers will be reported!!​

Answer 1

$\bigstar \: question \bigstar$

$12x {}^{\: 2} - 7x + 1$

= We can find two numbers

such that pq = 12×1=12, p+q= -7

_________________________

Here,

$= {12x}^{2} - \: 7x \: + 1 \ = 12x {}^{2} - 4x - 3x + 1 \ = 4x(3x - 1) - 1(3x - 1) \ = (3x - 1)(4x - 1)$

_________________________

*hope this helps u

Answer 2

Step-by-step explanation:

★question★

12x {}^{\: 2} - 7x + 112x

2

−7x+1

= We can find two numbers

such that pq = 12×1=12, p+q= -7

_________________________

Here,

= {12x}^{2} - \: 7x \: + 1 \ = 12x {}^{2} - 4x - 3x + 1 \ = 4x(3x - 1) - 1(3x - 1) \ = (3x - 1)(4x - 1)=12x

2

−7x+1 =12x

2

−4x−3x+1 =4x(3x−1)−1(3x−1) =(3x−1)(4x−1)