Question

$\huge \fbox \red{❥ Question}$


The shadow of a tower standing on level ground is found to be 40 m longer when the Sun’s altitude is 30° than when it is 60°. Find the height of the tower.


gud luck :-\​

Answer 1

Answer:

In △ABD,

tan60o=BDAB

3=xh

∴   x=3h                ------- ( 1 )

Now in △ABC,

tan30o=BCAB

⇒  31=x+40h

⇒  x+40=3h

∴  3h+40=3h          [  From equation ( 1 ) ]

⇒  h+403=3h

⇒  2h=403

∴  h=203m

∴  The height of a tower is 203m.

HOPE THIS HELPS YOU PLEASE MARK IT AS BRAINLIEST

Answer 2

QUESTION ⬇

The shadow of a tower standing on level ground is found to be 40 m longer when the Sun’s altitude is 30° than when it is 60°. Find the height of the tower?

ANSWER ⤵

»—>When the sun's altitude is at 30∘, ∠ADB=30∘and the length of the shadow=DB. So the length of the shadow is 40m when the angle changes from 60∘ to 30∘. That is CD=40m.

$\huge \colorbox{</em></strong><strong><em>r</em></strong><strong><em>e</em></strong><strong><em>d</em></strong><strong><em>}{❥ᴛʜᴀ᭄ɴᴋs}$